I was just thinking the other day, about the mathematics of a ballot. As our country's General Election is possibly coming up soon, it was a reasonable time to think about things a bit. I have to admit that I'm not a Political Scientist and so, I may not know what I'm talking about. However, I am also quite worried about the kind of FUD that both our Gahmen and Opposition are spreading.
The FUD that I'm referring to is that a voter has to either vote for BN or the Opposition in the straight fights that our country's politics has relegated itself to. They try to drum into the voters head that we have to either cross out BN or Opposition on the ballot sheet, in order to make our voices heard. This situation is a blatant lie and they know it. Actually, all politicians worldwide know it. They just don't want other people to see it.
Since I'm an enginner, I'll look from a mathematical point of view.
Problem: There is a ballot sheet with two boxes on it. One is labelled BN while the other is labelled Opposition. A voter, who has decided to go to the polls to have his/her voice heard, is asked to make a choice by crossing out any of the boxes according to his/her preference. By selecting a random voter, determine the possible outcomes of the single vote.
Gahmen's Truth: There is only one choice, of course cross out BN lar!
Opposition's Truth: There is only one correct choice, of course cross out Opposition lar!
Mathematical Truth: With two boxes and the possibility of crossing out any box, there are four possible outcomes, namely:
- Cross out the box labelled BN.
- Cross out the box labelled Opposition.
- Cross out both boxes labelled Opposition and BN.
- Cross out neither of the boxes and leave both empty.
- Supports BN.
- Supports the Opposition.
- Supports neither the Opposition nor BN.
PS: If you think that this still only means that there are only three possible outcomes, i.e. BN, or Opposition or spoilt vote, please think again!